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Fan Selection and Pressure Drop Matching Calculation Example

Aug 13, 2026 123 views ~8 min read Technical Knowledge
The heat saved by a heat exchanger can be eaten up by a wrongly selected fan. This article calculates the system total pressure drop and fan shaft power with an example, clarifying the relationship of "air volume vs. pressure drop, pressure drop vs. electricity cost," to avoid turning energy saving into power wasting.

I. Where System Pressure Drop Comes From

The total pressure drop of a heat exchange system = heat exchanger body + piping + air outlet/filter + elbows and reducers. If any link is enlarged, the fan electricity bill rises with it. Still taking the 12000 m³/h air volume as an example, assume a system total pressure drop of 350 Pa.

II. Calculate Fan Shaft Power

Air volume Q = 12000 / 3600 ≈ 3.33 m³/s, fan efficiency η taken as 0.6:

P = Q · Δp / η = 3.33 × 350 / 0.6 ≈ 1942 W ≈ 1.94 kW

Annual operation 8000 hours, electricity cost ≈ 1.94 × 8000 × 0.7 ≈ 10,900 RMB.

III. The "Square Penalty" of Pressure Drop

Approximately Δp ∝ u²; raising the wind speed by 20% increases pressure drop by about 44%, and the electricity bill rises accordingly. Therefore:

  • Do not design the flow channel too narrow, avoiding needless high velocity;
  • Select filter and heat exchanger by resistance; do not leave excessive margin "for safety";
  • Select the fan in its high-efficiency zone; a 10%~20% margin is enough, too large and it operates year-round away from the high-efficiency point.

IV. Selection Checklist

ItemPractice
Air volumeBy max condition + 10% margin
Total pressureSystem total resistance + 10%~20% margin
EfficiencySelect the point on the fan characteristic curve's high-efficiency zone
Variable frequencyUse VFD when load fluctuates greatly, supply air on demand
The heat exchanger's gain is in heat, the fan's cost is in electricity; the two must be put on the same ledger.

Related Reading

Keywords: fan selection pressure drop calculation shaft power air volume matching energy saving
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